(x-3)(x-5)(x-6)(x-10)=24^2

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Solution for (x-3)(x-5)(x-6)(x-10)=24^2 equation: 



(x-3)(x-5)(x-6)(x-10)=24^2

We move all terms to the left:

(x-3)(x-5)(x-6)(x-10)-(24^2)=0

We add all the numbers together, and all the variables

(x-3)(x-5)(x-6)(x-10)-576=0

We multiply parentheses ..

(+x^2-5x-3x+15)(x-6)(x-10)-576=0

We multiply parentheses ..

(+x^2-5x-3x+15)(+x^2-10x-6x+60)-576=0

We move all terms containing x to the left, all other terms to the right

(+x^2-5x-3x+15)(+x^2-10x-6x+60)=576

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